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Post by andrewtoplis on Dec 22, 2005 22:35:40 GMT
Hi All,
Does anyone know the formula for calculating the nominal tractive effort of a locomotive? Its in the Martin Evans book but I dont have a copy.
Thanks,
Andy
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gwrfan
Part of the e-furniture
Posts: 458
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Post by gwrfan on Dec 22, 2005 23:10:41 GMT
Hi Andy,
Here is the formula:
Tractive Effort =
B2 X S X P __________ lb ........W
Where B is the diameter of cylinders in inches. (B2 is actually B squared, but I couldn't uplift the 'B'!)
S is the stroke of cylinders in inches.
P is the effective steam pressure in lb. per sq inch.
W is the diameter of the driving wheels in inches. ( the dots are to enable me to keep the W in the centre!!)
If you need the rest of the pages, just holler and I'll copy it for you.
Geoff
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jackrae
Elder Statesman
Posts: 1,335
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Post by jackrae on Dec 23, 2005 7:48:49 GMT
Surely there should be a factor relating to the number of cylinders. If this is for a 2-cylinder engine then a 3 or 4 should produce greater tractive effort.
Jack
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Post by Richardw on Dec 23, 2005 10:16:46 GMT
Whilst GWRFAN has quoted the formula in Martin Evans Book I have seen and used the following formula which gives results that match published T.E. figures for full size Locomotives that includes a factor for the number of cylinders.
Tractive Effort lb =
N x D2 x S x P x 0.85 ___________ 2 x W
Where N=No of Cylinders D=Cylinder Diameter in inches S=Stroke in inches P=Bolier Pressure in psi 0.85 adjusts for the usual british practice of working out T>E> at 85% boiler pressure W=Wheel diameter in inches
This formula has worked okay for the 2,3 & 4 cylinder types I have tried working out.
Regards Richard
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Post by andrewtoplis on Dec 27, 2005 23:22:58 GMT
Magic!! Thanks guys.
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